In the title compound, C10H6BrNO3S, the dihedral angle between the thiazolidine ring (r.m.s. deviation = 0.014 angstrom) and the benzene ring is 5.78 (14)degrees. The S atom of the heterocyclic ring is syn to the OH group attached to the benzene ring. In the crystal, inversion dimers linked by pairs of N-H center dot center dot center dot O hydrogen bonds generate R-2(2)(8) loops. The dimers are linked into  ribbons by pairwise O-H center dot center dot center dot O hydrogen bonds with R-2(2)(18) motifs. There are no short contacts involving the Br atom.